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thedore
11-22-2009, 11:50 AM
Lesson in Electrochemistry....

We know that:
1 liter = (approximately) 1 quart.
1 amp of electricity 376 x 10^18 electrons per minute
1 mole of a gas = 22.4 liters
1 mole of a gas = 6.02 x 10^23 molecules (Avogadro’s number).


Start with 2 molecules of water then change to moles

H2O + H2O + 2 electrons = H2 + H2 + O2

or 1 mole + 1 mole + 2 electrons = 1 mole + 1 mole + 1mole

or 22.4 L + 22.4 L + electrons = 22.4L + 22.4 L + 22.4 L


If we assume the above all takes place in one minute then the number of amps required to change 2 moles of water ( 36 grams) to HHO gas is equal
to 12.02 x 10^23 / 376 x 10^18 = 3,190 amps.


But this current produces 67 liters of gas in one minute so the amount of electricity to produce 1 liter of gas per minute is .. 3,190 / 67 = 47 amps.


Ted

NOVICE
12-31-2009, 04:45 PM
The formulae that you are using to work out the power consumption of a cell, is all very well and fine. but if you consider the amount of amps that your alternator can produce to charge your car's battery in the first place, and the amp hours life of the battery. Plus the time of year and the amount of day light for this time of year,
You will soon be running your system at a non charge situation.( especialy if you are doing alot of night time driving.)
For instance if you have a 65 Amp alternator and a 45 Amp hour battery. Your battery will soon become flat because of the amount of discharge with all of your electrical equipment on the car being used to the maximum.
Even if you are regulating the max amount of amps to your HHO generator. The alternator will not be able to keep up with the recharge cycle.

Have you any sugestions as to how you can overcome this situation.
My car is a Rover 45. 2004 model. 1.4cc.

Llew2_1
01-19-2010, 12:39 PM
What I am doing is building in a DC electric welder for my Ford Ute. Going to remove the A/C comprssor and mount it there. This will completely power my HOD indipendantly of the vehicles electrical circuit. You could also use a bus Altrenator, but it does not have the welders control system.

thedore
02-07-2010, 09:11 PM
T
Have you any sugestions as to how you can overcome this situation.
My car is a Rover 45. 2004 model. 1.4cc.


Yes. The way is to series 3 or 4 cells together. With 4 cells the current becomes 57 / 4 or 14 amps. This is easy to get. ( my set up had 4 cells but I had to cut back to 3 as there was too much voltage loss in the current limiter. I plan to make changes to it. ) My present set up is about 3/4 LPM at a current of 18 amps.