thedore

11-22-2009, 11:50 AM

Lesson in Electrochemistry....

We know that:

1 liter = (approximately) 1 quart.

1 amp of electricity 376 x 10^18 electrons per minute

1 mole of a gas = 22.4 liters

1 mole of a gas = 6.02 x 10^23 molecules (Avogadro’s number).

Start with 2 molecules of water then change to moles

H2O + H2O + 2 electrons = H2 + H2 + O2

or 1 mole + 1 mole + 2 electrons = 1 mole + 1 mole + 1mole

or 22.4 L + 22.4 L + electrons = 22.4L + 22.4 L + 22.4 L

If we assume the above all takes place in one minute then the number of amps required to change 2 moles of water ( 36 grams) to HHO gas is equal

to 12.02 x 10^23 / 376 x 10^18 = 3,190 amps.

But this current produces 67 liters of gas in one minute so the amount of electricity to produce 1 liter of gas per minute is .. 3,190 / 67 = 47 amps.

Ted

We know that:

1 liter = (approximately) 1 quart.

1 amp of electricity 376 x 10^18 electrons per minute

1 mole of a gas = 22.4 liters

1 mole of a gas = 6.02 x 10^23 molecules (Avogadro’s number).

Start with 2 molecules of water then change to moles

H2O + H2O + 2 electrons = H2 + H2 + O2

or 1 mole + 1 mole + 2 electrons = 1 mole + 1 mole + 1mole

or 22.4 L + 22.4 L + electrons = 22.4L + 22.4 L + 22.4 L

If we assume the above all takes place in one minute then the number of amps required to change 2 moles of water ( 36 grams) to HHO gas is equal

to 12.02 x 10^23 / 376 x 10^18 = 3,190 amps.

But this current produces 67 liters of gas in one minute so the amount of electricity to produce 1 liter of gas per minute is .. 3,190 / 67 = 47 amps.

Ted