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View Full Version : How Much Energy in Joules does it take to split 1 litre of water???



Macca
03-01-2011, 06:00 AM
Hi guys,
Im trying to understand the numbers here,

1 Litre of water = 1886 litres of HHO gas

According to posts on this forum, 1 Litre of HHO = 12670 joules of energy

Which means 1 Litre of Water = (12670 x 1886) Joules (So thats 23895620 Joules)

Im not a great mathematician so could one of you clever people do the math of how much energy in joules it will take to split a litre of water?

If that figure is less than 23895620 Joules then we are onto a winner!!!!!!!:D

Macca
03-14-2011, 08:32 AM
No responses?

Ok I know that

1 Watt = 1 joule per second

and also that

Voltage x Current = Watts !!!

Hope this helps and that someone can help me!!

charliebrumfield
03-20-2011, 07:04 PM
No responses?

Ok I know that

1 Watt = 1 joule per second

and also that

Voltage x Current = Watts !!!

Hope this helps and that someone can help me!!

let me take a quick stab at this. i'm not mathematician but this seems to be a pretty simple equation to solve.

so lets say you have built the most efficient reactor possible and are getting the mythical 1 lpm of hho for 10 amps of juice.

13.4 volts (the volts you alternator puts out) x 10 amps = 134 watts

134 watts = 134 joules per second.

we have 60 seconds in 1 minutes so we are using 8040 joules for each liter of hho (134 joules x 60 seconds = 8040 joules)

if we have 1886 liters of hho in one liter of water then it takes us 1886 minutes to burn off the entire liter of water and we use 15163440 joules of energy to create the hho gas. (8040 joules x 1886 liters of hho = 1516440 joules used)

if we are able to get 12670 joules of energy from 1 liter of hho then we have 23895620 Joules in 1 liter of water (1886 liter of hho x 12670 joules).

23895620 joules in hho we produced > 15163440 joules of energy was used to create it.

but there is one problem with this theory...

the best reactors to day use close to 20 amps to produce 1lpm of hho. so that means we are using double the energy we are using to produce the hho.

15163440 joules of energy used in our previous equation x 2 (since reality doubles our amps from our theoretical 10 amps to 20 amps) = 30326880 joules are actually used to produce our 1886 liter of hho which only nets us 23895620 joules of energy.

so in reality we loose 21% of the energy we put in to splitting the hho during the process. probably in the form of heat and current leakage. (23895620 joules in hho produced / 30326880 joules of energy used to produce the hho leaves us with only 79% of the energy we originally put in.)

so we still have a net negative energy process. and there is still no such thing as perpetual motion. :p