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Thread: Feeding only hho into the air intake?

  1. #1
    jerzhere Guest

    Feeding only hho into the air intake?

    I saw a youtube video where a guy taped off his air filter so only HH0 was going into the air intake.

    This concept beings up some interesting questions.

    1. How much HHO would you have to produce to assure the engine gets the amount of air (in this case HHO) it needs during all levels of operation?

    2. Would this cause a vacuum that would suck the water into the engine and/or cause the cell / bubbler to implode?

    3. Assuming you can achieve #1 and stop #2, would this increase the efficiency and perhaps help to get around issues related to 02 sensors.

    Logically speaking, if you only feed HHO into the air intake you could control the 02 levels much better. Now you can say, ok, I have X amount of HHO being feed into the engine and X amount of gas and not have to worry about the 02 being pulled in from the open air. Seems like this would give you greater control and improve the overall efficiency of HHO. On the other hand, achieving this may be a nightmare

  2. #2
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    I've thought about this too. I tried taping the air cleaner on my suburban and the idle got really rough and it felt like the power loss was significant. But my generator was only making 1lpm.
    I've thought about it too. Of the percentage of oxygen in HHO would be 30% and isn't that fairly close to what is in the air we breathe?
    But the issue is it would work ok at idle, but at WOT the car would be very starved out. If you could build a valve that would open at a certain time when under heavier load that might work.

  3. #3
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    I was thinking about it, about how many lpm do car's use for air volume. If you could figure out how much your car uses at WOT you could regulate the amount of hho to regular incoming air and make sure the car is not starving. Maybe with poteniometer tied to a PWM could be attached to the throttle.

  4. #4
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    Quote Originally Posted by velorossa22 View Post
    I was thinking about it, about how many lpm do car's use for air volume. If you could figure out how much your car uses at WOT you could regulate the amount of hho to regular incoming air and make sure the car is not starving. Maybe with poteniometer tied to a PWM could be attached to the throttle.
    Air volume on the intake manifold is measured in Cubic Feet per Minute (CFM).

    http://www.ajdesigner.com/phpengine/..._flow_rate.php

    Even my motorcycle requires 140+ CFM. Our measly amount of HHO would never be able to replace the entire volume of air needed by the engine.
    --
    Some days I get the sinking feeling that Orwell was an optimist!

  5. #5
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    yeah I looked it up and it basically computes out to L x rpm. Even if you divide it by 5 ( since you're feeding close to 100 % O2 instead of 20% in regular air) you're still way short.

  6. #6
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    Quote Originally Posted by Q-Hack! View Post
    Air volume on the intake manifold is measured in Cubic Feet per Minute (CFM).

    http://www.ajdesigner.com/phpengine/..._flow_rate.php

    Even my motorcycle requires 140+ CFM. Our measly amount of HHO would never be able to replace the entire volume of air needed by the engine.
    There is no way I would try to start any engine with only HHO and no atmosphere entering the combustion chamber. I am afraid the explosion would blow the heads right off. Although it would take a tremendous amount of HHO to get an engine to even idle it never would require 100% or even close to that amount. There would be plenty of force generated at far below those amounts of HHO. It would be fun to have a normal V8 on a bench hooked up and ready to run just to see how much it would take to get it to idle. Every time this question is posed everyone always assumes that you would have to supply the entire volume the engine intakes to get the job done.

    Larry
    2008 Nissan Frontier 4X4 Nismo. 12 MPG baseline with my normal commute and heavy stop and go daily driving. Generator installed and working on 3/29/2009

    Up to 14.5 MPG with no enhancers. Still testing the effects of lots of HHO and no electronic enhancers.

  7. #7
    JOHNM Guest
    jerzhere

    SOME PEOPLE SAY THEY ARE RUNNING 100% HHO. THEY WILL HAVE A COMPLETE ENGINE FAILURE (MELTDOWN) UNLESS THEY DO A LOT OF ENGINE WORK. I CAN'T GET INTO DETAILS BECAUSE OF PATENT CONCERNS. SO WHOEVER IS DOING 100% HHO BETTER HAVE A LOT OF CASH IN RESERVE.

    I'VE DONE SOME WORK ON VEHICES HERE ARE SOME PICS. FIRST ONE IS A FORD 460 ENGINE IT EMPTIES 6ea 255 CUBIC FEET BOTTLES OF HYDROGEN IN 10 MINUTES OF RUNNING AT 2500 RPM

    http://photos.thedieselstop.com/show...417/ppuser/198 NOTE THE EXHAUST PIPES TEMP

    IT WENT INTO THIS
    http://photos.thedieselstop.com/show...418/ppuser/198

    ALSO WORKED ON THIS
    http://photos.thedieselstop.com/show...401/ppuser/198 THIS WENT 3,469.5 MPG

    AND THIS
    http://photos.thedieselstop.com/show...409/ppuser/198 THIS REACHED 55 MPH

    AND THIS IS A STERLING CYCLE ENGINE CONVERTED TO HHO. 4 CYL 40 HP ABOUT THE SIZE OF A OLD VW AIR COOLED ENGINE.
    http://photos.thedieselstop.com/show...413/ppuser/198

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    Sorry, it takes me so long to respond. I have difficulty typing and seeing small type. I can read better if it is in caps, so I'm not shouting, just trying to see what I type.

    Soon to add HHO to both
    2004 VW Golf TDI - Automatic, 100 HP Diesel gets 40 MPG around town.

    2001 Monaco Knight - 265 HP Cummins gets 12.5 MPG towing the TDI

  8. #8
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    Well I am a newbie, but read that a throttled 2.0 engine would need a 100 to 500 LPM (volume) of (mixture of) gases thru the combustion chambers. Usually the gasoline engine will intake atmospheric air and mix it with a gasoline mist...

    Our cells wouldn't be able to furnish that amount of hho gas.. anybody has the right numbers for engine flow?

  9. #9
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    Nov 2009
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    This is a logical idea, untill you think about it more. ICE's are made to mostly pump nitrogen, to use just HHO you would need a extremely high vacuum. It would be more reasonable to make an engine specifically for hho.
    I=V/R so R=V/I and V=I*R
    P=V*I
    (I=Amps, V=volts, P= power in watts, R=resistance in ohms)

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