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Thread: Is it realy possible to make enough hho to run 100%hho

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  1. #1
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    Mar 2010
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    Is it realy possible to make enough hho to run 100%hho

    Hi yes im a newbie

    Can you produce enough hho to run completly on it and if so how many cells and how many pulse gens would you need what is a dry cell a apposed to a wet cell in basic terms please
    Dave

  2. #2
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    Mar 2010
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    You would need an immense amount of HHO to make even a small engine run solely on HHO.
    This is a copy and paste I got from one source. I am not this smart, I'm not sure if this guy is, but here's what he's gotta say:

    The amount of oxyhydrogen needed to run an internal combustion engine is spectacular. Idling a small engine (e.g. 5hp) would require 500-1000 LPH (liters per hour), while idling a car engine would probably consume about 3000LPH of oxyhydrogen. Driving down the highway would probably consume 20000-30000 LPH of oxyhydrogen.
    I'll hang up and listen to your answer.

  3. #3
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    Jul 2008
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    The short answer is no. Like N11634 said it would take way too much gas to run an engine entirely on HHO. The problem is we are all trying to force feed HHO down an engine that it was not designed for. While it can help combustion and give good results, it is tricky at best. To get the full potential of HHO we need to design a new engine around the fuel. But make no doubt about it HHO is a great fuel. We just don't know enough about it, help us figure it out!

  4. #4
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    A simple proof of a ballpark figure is to look at the combustion process of an internal combustion engine. Every second, the engine goes through X cycle. At idle, this "X" cycles might be 600 rotations per minute, or 10 rotations("cycles") per second. That means the engine cylinder sucks in fuel, compresses it, combusts it, and expels the exhaust. For normal 4-stroke engines, the number of cycles is actually half the rotations per second, so in this example the engine sucks in a full cylinder of fuel 5 times per second.

    Now, assuming this is a small 2.0 liter engine, this means that it will suck in 2 liters of fuel mixture 5 times a second. That is 10 liters of fuel mixture per second, or 600 liters per minute.

    Of course, this is an oversimplified example, but it should give you an idea of the magnitude of gas that you are wondering about. There are more complicated models involving HHO to air ratio, gas expansion at the given speed, etc. etc., but this should give an upper bound for just an idling speed - ~600 liters per minute.

  5. #5
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    Feb 2010
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    los angeles , california
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    The engine that we use are design to run on gasoline. It would take too much hho to run it, so don't even bother. Hho gas burn fast and powerful. To redesign the engine to run soley on hho. the piston distance of motion sould be alot shorter because hho does not continue burning like gas and diesal does and the timming short be delayed.

  6. #6
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    Quote Originally Posted by Philldpapill View Post
    A simple proof of a ballpark figure is to look at the combustion process of an internal combustion engine. Every second, the engine goes through X cycle. At idle, this "X" cycles might be 600 rotations per minute, or 10 rotations("cycles") per second. That means the engine cylinder sucks in fuel, compresses it, combusts it, and expels the exhaust. For normal 4-stroke engines, the number of cycles is actually half the rotations per second, so in this example the engine sucks in a full cylinder of fuel 5 times per second.

    Now, assuming this is a small 2.0 liter engine, this means that it will suck in 2 liters of fuel mixture 5 times a second. That is 10 liters of fuel mixture per second, or 600 liters per minute.

    Of course, this is an oversimplified example, but it should give you an idea of the magnitude of gas that you are wondering about. There are more complicated models involving HHO to air ratio, gas expansion at the given speed, etc. etc., but this should give an upper bound for just an idling speed - ~600 liters per minute.
    You know from what I have learned One Liter of water expands into 30 liters of HHO, correct? So one gallon should make 30 gallons of HHO, correct? Now Meyers already demonstrated over and over that his car was able to produce enough gas to run that Dune buggy engine off straight HHO and from his mileage he estimated 22 gallons of water could get him from LA to New York, correct? So 22 gallons X 30 = 660 gallons of HHO Now according to a conversion site "About 3.79 liters make a US gallon" so Multiple 660 gallons X 3.79 = 2501.4 liters. Some people are trying to say to run a small car engine it would take close to 150 liters per minute of HHO? so divide the 2501.4 liters by 150 liters and that means in 16.676 minutes you would have used up all of the 22 gallons of water? That does not figure right at all! There is no way you could drive from LA to New York in 16.676 minutes of HHO production according to some of the stuff I read out there. So from my simple deductive reasoning and from the fact that many scientists and people in general saw Meyer's invention work and work good I believe there is a lot of false propaganda out there on the internet trying to dissuade anyone else from working on Meyer's WFC type HHO production. The distance from LA to New York is roughly 2443.79 miles. So divide 2443.79 miles by 22 gallons and you have the miles per gallon of 111.0813636363636 MPG of water roughly and remember Meyer's motor was a 1.6 liter engine in that Dune Buggy of his is a small engine. I have a 5.0 liter engine. I would need about four of those large WFC's of Meyers at least to run that thing. If my math is wrong please enlighten me?

    Oh and from what I learned also the more SS 304 Tubes Sets you add the more efficient the WFC becomes. So adding 3 more sets of tubes would not take much more juice to power it than just the one set took.

    Also Ravi was suppose to have got a high output using the small 4" tubes so using a whole bunch of those seems like it would be enough to run a car or truck as in my case on straight HHO.

    One other simple deductive reasoning point. The US Patents office is reluctant to give patents to these types of inventions that produce or claim to produce 1,700% efficiency as Meyer's claims. Yet they did! The only way they would have is if he proved it beyond a reasonable doubt to that office which he did otherwise it would not have happened!

  7. #7
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    May 2008
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    189
    actually one litre of water decomposes to 1200 litres of hho

  8. #8
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    Nov 2009
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    San Diego, California.
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    337

    Take a basic chemistry class please . . .

    Quote Originally Posted by HawkNo1 View Post
    You know from what I have learned One Liter of water expands into 30 liters of HHO, correct? So one gallon should make 30 gallons of HHO, correct? Now Meyers already demonstrated over and over that his car was able to produce enough gas to run that Dune buggy engine off straight HHO and from his mileage he estimated 22 gallons of water could get him from LA to New York, correct? So 22 gallons X 30 = 660 gallons of HHO Now according to a conversion site "About 3.79 liters make a US gallon" so Multiple 660 gallons X 3.79 = 2501.4 liters. Some people are trying to say to run a small car engine it would take close to 150 liters per minute of HHO? so divide the 2501.4 liters by 150 liters and that means in 16.676 minutes you would have used up all of the 22 gallons of water? That does not figure right at all! There is no way you could drive from LA to New York in 16.676 minutes of HHO production according to some of the stuff I read out there. So from my simple deductive reasoning and from the fact that many scientists and people in general saw Meyer's invention work and work good I believe there is a lot of false propaganda out there on the internet trying to dissuade anyone else from working on Meyer's WFC type HHO production. The distance from LA to New York is roughly 2443.79 miles. So divide 2443.79 miles by 22 gallons and you have the miles per gallon of 111.0813636363636 MPG of water roughly and remember Meyer's motor was a 1.6 liter engine in that Dune Buggy of his is a small engine. I have a 5.0 liter engine. I would need about four of those large WFC's of Meyers at least to run that thing. If my math is wrong please enlighten me?

    Oh and from what I learned also the more SS 304 Tubes Sets you add the more efficient the WFC becomes. So adding 3 more sets of tubes would not take much more juice to power it than just the one set took.

    Also Ravi was suppose to have got a high output using the small 4" tubes so using a whole bunch of those seems like it would be enough to run a car or truck as in my case on straight HHO.

    One other simple deductive reasoning point. The US Patents office is reluctant to give patents to these types of inventions that produce or claim to produce 1,700% efficiency as Meyer's claims. Yet they did! The only way they would have is if he proved it beyond a reasonable doubt to that office which he did otherwise it would not have happened!
    Your inability to perform a simple water to HHO calculation does not give you much credibility. Your assumption that the Meyer machine must work because the Patent office granted a patent, shows your naivety about patent law - a set of drawings and prior art can get you a patent. A working prototype is NOT a requirement. A patent grant does not prove your device works, it only gives the right to legally sue in a court of law.

  9. #9
    Join Date
    Apr 2010
    Posts
    4
    Quote Originally Posted by HawkNo1 View Post
    You know from what I have learned One Liter of water expands into 30 liters of HHO, correct? So one gallon should make 30 gallons of HHO, correct? Now Meyers already demonstrated over and over that his car was able to produce enough gas to run that Dune buggy engine off straight HHO and from his mileage he estimated 22 gallons of water could get him from LA to New York, correct? So 22 gallons X 30 = 660 gallons of HHO Now according to a conversion site "About 3.79 liters make a US gallon" so Multiple 660 gallons X 3.79 = 2501.4 liters. Some people are trying to say to run a small car engine it would take close to 150 liters per minute of HHO? so divide the 2501.4 liters by 150 liters and that means in 16.676 minutes you would have used up all of the 22 gallons of water? That does not figure right at all! There is no way you could drive from LA to New York in 16.676 minutes of HHO production according to some of the stuff I read out there. So from my simple deductive reasoning and from the fact that many scientists and people in general saw Meyer's invention work and work good I believe there is a lot of false propaganda out there on the internet trying to dissuade anyone else from working on Meyer's WFC type HHO production. The distance from LA to New York is roughly 2443.79 miles. So divide 2443.79 miles by 22 gallons and you have the miles per gallon of 111.0813636363636 MPG of water roughly and remember Meyer's motor was a 1.6 liter engine in that Dune Buggy of his is a small engine. I have a 5.0 liter engine. I would need about four of those large WFC's of Meyers at least to run that thing. If my math is wrong please enlighten me?

    Oh and from what I learned also the more SS 304 Tubes Sets you add the more efficient the WFC becomes. So adding 3 more sets of tubes would not take much more juice to power it than just the one set took.

    Also Ravi was suppose to have got a high output using the small 4" tubes so using a whole bunch of those seems like it would be enough to run a car or truck as in my case on straight HHO.

    One other simple deductive reasoning point. The US Patents office is reluctant to give patents to these types of inventions that produce or claim to produce 1,700% efficiency as Meyer's claims. Yet they did! The only way they would have is if he proved it beyond a reasonable doubt to that office which he did otherwise it would not have happened!
    You can patent pretty much anything unique, doesn't mean it's functional. And do we all agree that Wikipedia can be considered the foremost source of actual facts? (you should be nodding yes) Now, look up Stan Meyers on Wikipedia.

  10. #10
    Join Date
    Aug 2010
    Posts
    3
    Quote Originally Posted by Philldpapill View Post
    A simple proof of a ballpark figure is to look at the combustion process of an internal combustion engine. Every second, the engine goes through X cycle. At idle, this "X" cycles might be 600 rotations per minute, or 10 rotations("cycles") per second. That means the engine cylinder sucks in fuel, compresses it, combusts it, and expels the exhaust. For normal 4-stroke engines, the number of cycles is actually half the rotations per second, so in this example the engine sucks in a full cylinder of fuel 5 times per second.

    Now, assuming this is a small 2.0 liter engine, this means that it will suck in 2 liters of fuel mixture 5 times a second. That is 10 liters of fuel mixture per second, or 600 liters per minute.

    Of course, this is an oversimplified example, but it should give you an idea of the magnitude of gas that you are wondering about. There are more complicated models involving HHO to air ratio, gas expansion at the given speed, etc. etc., but this should give an upper bound for just an idling speed - ~600 liters per minute.

    Good estimate, but you're forgetting something. After the throttle body, you see a vacuum. The air the engine sucks in isn't at 100% atmospheric pressure, so the amount would be less. Sometimes much less. At idle, it may be 1/20th just to pull a guess out of my head. Of course, it would go up quite a bit as the throttle opens and the rpms increase.

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