The Best Cell Ive seen

[BoyntonStu]

"A watched pot never boils"

[ICEMAN.KCMO]

which one of those tubes is the pos? and where did you get those tubes???

[HomeGrown]

The center tube is pos. I got the tubing from www.smallparts.com
I'm about 80% done with my rebuild, and hopefully the third time is a charm. The bench-tested model worked well on just plain tap water, although I didn't have a setup to measure LPM.

[BoyntonStu]

I'm currently working on my tube cell. I had it built once, but decided to rebuild it because I got ahold of a 3" stainless steel tube for a housing. It previously fit inside a 4" PVC pipe, but I'm not wanting to use PVC at all. I've also modified my individual cells to have 3 electrodes instead of 2. My outer tube is 1.00", middle tube is .75", and the inside tube is .50". There is a .06 gap (1.5mm) between the tubes. I've devised a spacing method where the center tube holds the spacers for both the inner and outer tubes. I posted this pic on another thread, but here it is again, and shows the spacers both in-place in the center tube, and laying on the bench. The new cell will consist of 7 individual 3-tube cells. I originally tried to use the center tube as a neutral or unconnected, but I didn't like the results. When I hooked power up to all 3 though, WOW.
Definately will need to look for some sort of voltage/current control for this thing. I really like the idea of tube design, as it minimizes current leakage. The positive charged tube is isolated from the rest of the water in the cell.

Did you wire your 3 tubes -+- or +-+?

What difference did you observe?

The center tube of a 3 tube cell produces gas from both sides, correct?

How long are the tubes?

BoyntonStu

[HomeGrown]

I actually tried the tubes in both configurations, and the output appeared to be only slightly more in the -+- configuration. No LPM measurements, just seat-of-the-pants observation.

Yes, output from both sides. I originally put the 3rd tube (the .5" tube) in so the center (.75") tube would then be unconnected. This didn't seem to work very well, so I once again revamped it to add power, and was pleased with the results. The new configuration that I'm currently (re)building will be -+- because I'm working with a 3" stainless tube for the housing (actually 3.25" i.d.), which itself will be negative in polarity. I'm unsure how well my endcaps will hold up though, because I'm using UHMW. Stuff machines like Ivory soap, but it's only rated @ 180 deg. continuous, 210 deg. non-continuous peak. If the cell performs well I may opt to make endcaps out of more appropriate material.

The 1.00" dia. tubes are 5" long, .75" tubes are 5.3", and the .50 tubes are 6" in length. There will be 7 sets of 3 tubes in a tight cluster.

[BoyntonStu]

I actually tried the tubes in both configurations, and the output appeared to be only slightly more in the -+- configuration. No LPM measurements, just seat-of-the-pants observation.

Yes, output from both sides. I originally put the 3rd tube (the .5" tube) in so the center (.75") tube would then be unconnected. This didn't seem to work very well, so I once again revamped it to add power, and was pleased with the results. The new configuration that I'm currently (re)building will be -+- because I'm working with a 3" stainless tube for the housing (actually 3.25" i.d.), which itself will be negative in polarity. I'm unsure how well my endcaps will hold up though, because I'm using UHMW. Stuff machines like Ivory soap, but it's only rated @ 180 deg. continuous, 210 deg. non-continuous peak. If the cell performs well I may opt to make endcaps out of more appropriate material.

The 1.00" dia. tubes are 5" long, .75" tubes are 5.3", and the .50 tubes are 6" in length. There will be 7 sets of 3 tubes in a tight cluster.

I calculate that the equivalent cell plate area is 66 sq inches x 2 (for both sides of the .5 tube)

pi x .5 x 42" for one side

Having the container - allows grounding to the frame.

Boyntonstu

[HomeGrown]

I calculate that the equivalent cell plate area is 66 sq inches x 2 (for both sides of the .5 tube)

pi x .5 x 42" for one side

Having the container - allows grounding to the frame.

Boyntonstu

The .5 tube is the smallest tube. If gas production is on the - side, then it would have to be calculated on the i.d. of the 1.00 tube (.87) and on the o.d. of the .5" tube, which would be:

.5 x 3.14 x 5.3 x 7 = 58.247 (gas production area is only calculated on the tube length of the shorter .75" tube)

plus

.87 x 3.14 x 5 x 7 = 95.613

for a total production area of 153.86 sq. in.

For a brief moment I was considering not connecting the 1.00" tubes to the cell housing, and just allowing the electrolyte to create the connection between the housing and the tubes. But I figured that would only serve to create more heat, so I scrapped that idea.

[BoyntonStu]

Sorry, but I believe that it is the smallest link in the chain that is counted.

IOW Imagine a 6x6 plate and a 1x1 plate.

The cell would be a 1 sq in cell.

Correct me if I am wrong.


BoyntonStu

[HomeGrown]

Sorry, but I believe that it is the smallest link in the chain that is counted.

IOW Imagine a 6x6 plate and a 1x1 plate.

The cell would be a 1 sq in cell.

Correct me if I am wrong.


BoyntonStu

What part of that calculation do you not agree with? The shortest link of a chain does not define the total length of the chain.

My calculation of 153.86 represents the true working surface area of the cell: all negative, gas-producing surfaces.

In your calculation, you've calculated the actual length of the .5 tube, not the effective length. You've also (mis)calculated the inside of the .5 tube (.40 dia.), which does not produce gas.

To recap, gas is produced on the o.d. of the .50" tubes and on the i.d. of the 1.00" tubes.

[Boltazar]

Homegrown Series or parallel How do you get power to the electrodes