A formula for Amperage.. Where V=Volts, I=Amps, R=Ohms is the resistance measured in Ohms... V=IR so, Resistance we would need to overcome with an electrolyte would be: R=V/I R=12/15=.8 Ohms (12 volts(V), 15 Amps(I).

Do you know how many Ohms KOH & NaHo give in say a litre of water.

According to the article, you would have to have I=12/.1=120amps for a resistance of .1 Ohms.

He is a clip from an article I found online..

Let's start with the simple equation V = IR. The equation can be rearranged to I = V/R. 6 volts flowing across a resistance of 2 ohms would give a current of 3 amperes. A strong solution of electrolyte will have a very low R, nowhere near a full ohm and usually much less than 1/10 of an ohm. Thus, the value of I will be very high unless one introduces some more resistance to the circuit. Keep in mind that R for a solution depends on the path length, just as it does in a wire; electrodes farther apart in the solution will allow less current to flow.