What is the formula for knowing how much hho is needed for a particular engine? I have a 3.3L fuel injected V6 Nissan Xterra 2003.
What is the formula for knowing how much hho is needed for a particular engine? I have a 3.3L fuel injected V6 Nissan Xterra 2003.
Tim,
The basic formula is half of the displacement.
For your 3.3L engine, the best starting point would be 1.65 liters per minute of actual gas (not vapors).
1998 Explorer 4x4, 4.0
14 cell / 2 stack 6x9" drycell reactor 28%KOH dual EFIE, MAF enhancer, IAT & ECT controllers, 2.4 LPM @ 30 amps. 6.35 MMW http://reduceyourfuelbill.com.au/forum/index.php
Ok, I am new to this. How are you distinguishing gas-vs-vapor? I have seen folks measureing LPM using a liter bottle filed with water then bubbling into the bottle until the water is displaced. That seems like a rather simple test?
If you can see the output then it has water vapor. I always use Bob Boyce formula and i have had great results.
For gasoline vehicles .25-.5 LPM of hydrogen per L of the engine
For Diesel Vehicles .5-.75 LPM of hydrogen per L of the engine.
I hope that helped!
Hi Franco,
That's .25-.5 LPM for gasoline engines for how much mileage improvement?
Mileage improvement is based on how well you re-tune your vehicle to accept the addition of the hho gas. Increasing efficiency within your engine demands that you re-tune your vehicle to perform the same functions as before with simply less fuel.