I would like to apologize to everyone that I have inadvertently misguided. I thought that I completely understood, backwards and forwards the method and calculation for bipolar reactors, having had many discussions with lots of very knowledgeable HHO people and doing seemingly endless reading. It turns out that I was somehow misunderstanding (repeatedly) this process and method and have been overstating the necessary amperage required by a great amount.
The link I supplied, and myoldyourgold are correct, in that: 1/2A per sq. in. of working area of 1 plate, is the amperage required for a 1 stack reactor. A stack is [+nnnnnn-]. Two stacks are [+nnnnnn-nnnnnn+] and would use twice that amperage, three stacks = three times that amperage, or the working area of three plates times one half amp.
It is my sincere hope that I have not caused any harm to anyone or their property with my erroneous advice.
Gus